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Nirvana - where time stands still

For a distant observer, measured time slows to a standstill as an object approaches the event horizon of a Schwarzschild black hole.

With the new solution proposed here, every point inside the event horizon of a black hole is sitting on a local event horizon, where, for a distant observer, measured time would slow to a standstill (if it were visible). This follows because the metric function in Schwarzschild coordinates will always approach infinity at each (local) event horizon. When considering the path of an object 'falling through' the event horizon, one has to consider what happens to that path once time stands still. Further movement becomes impossible, so all paths terminate at the event horizon. In no sense does this violate Einstein's equivalence principle. The equivalence principle simply states that the results of any local experiment will not distinguish any change. When time stops, all experiments must cease and so no difference can ever be detected, as required by the principle. A different concern sometimes raised is the idea of infinity, as it were, just hanging in space. In fact, this idea is also a mistake. These points are at infinity on the time axis, and not on a spatial axis. It should cause no more undue concern than similar points at infinity on the extremities of the other three axes.

Now let us now look at the special properties of a body without the progress of time.

Truly rigid bodies->


Agree or disagree, or have any questions or observations about this, and I would love to hear from you, so please This email address is being protected from spambots. You need JavaScript enabled to view it., or leave a comment. Your views are always most welcome.


0 #1 Rodolfo 2020-02-28 17:15
You really make it seem so easy with your presentation but I find
this topic to be really something which I think I would never understand.

It seems too complicated and extremely broad for
me. I am looking forward for your next post, I'll try to
get the hang of it!

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